6x^2+14x-24=0

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Solution for 6x^2+14x-24=0 equation:



6x^2+14x-24=0
a = 6; b = 14; c = -24;
Δ = b2-4ac
Δ = 142-4·6·(-24)
Δ = 772
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{772}=\sqrt{4*193}=\sqrt{4}*\sqrt{193}=2\sqrt{193}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{193}}{2*6}=\frac{-14-2\sqrt{193}}{12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{193}}{2*6}=\frac{-14+2\sqrt{193}}{12} $

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